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Open a URL in foreground (app.open_url)

Declaration​

ok = app.open_url(URL)

Parameters​

Returns​

  • ok
    Boolean. Whether the URL was opened successfully.

Notes​

  • Open a URL in the foreground. Can open URL Scheme (see URL Scheme usage).
  • For some URLs, this API may not give the desired behavior. In a jailbreak environment you can try the uiopen shell command instead:
local function sh_escape(path) -- XXTouch original function; allowed for commercial use with credit
    path = string.gsub(path, "([ \\()<>\'\"`#&*;?~$|])", "\\%1")
    return path
end
os.execute('uiopen '..sh_escape('https://www.google.com'))
os.execute('uiopen '..sh_escape('prefs:root=SAFARI&path=CLEAR_HISTORY_AND_DATA'))

Example​

app.open_url("https://www.google.com") -- open Google in Safari (may not be accessible)
--
app.open_url("prefs:root=SAFARI&path=CLEAR_HISTORY_AND_DATA") -- Settings -> Safari -> Clear History and Website Data